To solve this problem you must follow the proccedure below:
 a. Find the perimeter and area of the cracker remaining:Â
 The perimeter of a quarter circle is:
 P=(πr/2)+2r
 P=(πx3 cm/2)+2(3 cm)
 P=10.71 cm
 The perimeter of the cracker remaining is:
 Pt=3 cm+6 cm+3 cm+10.71 cm
 Pt=22.71 cm
 The area of a quarter circle is:
 A=πr²/4
 A=π(3 cm)²/4
 A=7.06 cm²
 The area ofof the cracker remaining is:
 At=Area of a square-Area of quarter circle
 At=L²-(πr²/4)
 At=(6 cm)²-(π(3 cm)²/4)
 At=28.93 cm²
 b. About how many bites can you get from the entire cracker?Â
 Number of bites=L²/(π(3 cm)²/4)
 Number of bites=5