(2x−3)(x+4)=0space, left parenthesis, 2, x, minus, 3, right parenthesis, left parenthesis, x, plus, 4, right parenthesis, equals, 0 let x=ax=ax, equals, a and x=bx=bx, equals, b be the solutions to the equation above. what is the value of -a-b−a−bminus, a, minus, b?

(2x - 3) (x + 4) = 0

(2x - 3) = 0 or (x + 4) = 0

2x - 3 = 0
2x = 3
x = 3/2

x + 4 = 0
x = -4

---------------------------------------------------------------
Answer: x = 3/2 Or x = -4
---------------------------------------------------------------

Answer Link

lisboa lisboa · Answer 2 · 2019-05-18T03:46:01+02:00

lisboa lisboa

18-05-2019

Answer:

a-b= 5.5

Step-by-step explanation:

(2x−3)(x+4)=0

x=a and x=b , find out a-b

First we need to solve for x

(2x−3)(x+4)=0, Apply zero factor property and set each factor =0

2x-3=0

add 3 on both sides

2x=3

divide by 2 on both sides

x= 3/2

x+4=0 , subtract 4 from both sides

x= -4

[tex]x=a=\frac{3}{2}[/tex]

x=b=-4

a-b = [tex]\frac{3}{2}-(-4)= \frac{3}{2} +4 = \frac{3+8}{2} =5.5[/tex]

Answer Link