How much work can a 23,000 Watt car engine do in 35 seconds if it is 100% efficient?

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02-03-2018
Physics

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How much work can a 23,000 Watt car engine do in 35 seconds if it is 100% efficient?

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skyluke89 skyluke89 · Answer 1 · 2018-06-12T12:28:23+02:00

The power (P) is defined as the work done by the engine per unit of time:
[tex]P= \frac{W}{t} [/tex]
Where W is the work and t the time. If the efficiency of the engine is 100% (like in this case), all the work done is converted into useful power, so we can use the previous equation. By rearranging it and by plugging in the numbers (P=23000 W and t=35 s), we can find the work done by the car engine:
[tex]W=Pt=(23000 W)(35 s)=8.05 \cdot 10^5 J[/tex]

shirleywashington shirleywashington · Answer 2 · 2019-04-26T18:57:36+02:00

shirleywashington shirleywashington

26-04-2019

Answer:

Work done, W = 8,05,000 J

Explanation:

It is given that,

Power of car engine, P = 23,000 watt

Time taken, t = 35 s

The work done per unit time is called the power of the car engine.

[tex]P=\dfrac{W}{t}[/tex]

[tex]W=P.t[/tex]

[tex]W=23000\times 35[/tex]

W = 8,05,000 J

Hence, this is the required solution

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