In the figure, QS = 15, RT = 36, and RT is tangent to radius QR with the point of tangency at R. Find QT.

The length of QT is 39.
In the figure, QS = 15, RT = 36, and RT is tangent to radius QR.
The radius of a circle is perpendicular to the tangent line through its endpoint on the circle's circumference
Therefore, ΔQRT is a right triangle.
Bye using Pythagoras theorem
QT²=QR²+RT²
QR and QS are both radii, so QR=QS=15
QT²=15²+36²
QT=39
We get the length of QT is 39.
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