maddylm9
maddylm9
02-02-2018
Mathematics
contestada
Factor completely. 49 t6 - 4 k8
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choixongdong
choixongdong
02-02-2018
49 t^6 - 4 k^8
= (7t^3)^2 - (2k^4)^2
= (7t^3 + 2k^4)
(7t^3 - 2k^4)
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