Respuesta :

TheAakash
Let's convert the width to an improper fraction first:
[tex]6 \frac{2}{3} = \frac{6*3+2}{3} = \frac{20}{3} [/tex]

This means that the length is:
[tex] \frac{20}{3}*2 = \frac{40}{3} [/tex]

The perimeter of a rectangle is:
[tex]2(l+w)[/tex]

Plug in values, and you get:
[tex]2( \frac{40}{3}+ \frac{20}{3}) = 2(\frac{60}{3}) = \frac{120}{3} = 40 [/tex]

So, your answer is 40 in.

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