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A ball is thrown horizontally from a 19 m -high building with a speed of 2.0 m/s . How far from the base of the building does the ball hit the ground?

Respuesta :

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Using the formula: ΔY = V₀y * t + (1/2) * ay * t²

Solve for time and get: 1.968s

Then use: v = d/t in the x-direction and get: d = 3.936

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