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02-10-2017
Mathematics

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[tex] \sqrt{26x+13} = x+7[/tex]

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lucyfiennes lucyfiennes

02-10-2017

√26+13 ² = (x+7)²
26x + 13 = X² +14X + 49
26X +13 - X² -14X - 49 = 0
12X - X² - 36 = 0
-(X²-12X+36) = 0
-(X-6)² = 0
(X-6)² = 0
X-6 = 0
X= 6

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