Respuesta :

1)

[tex]\bf \textit{surface area of a cube}\\\\ s=6x^2\quad \begin{cases} x=\textit{length of a side}\\ ---------\\ s=150 \end{cases}\implies 150=6x^2\implies \cfrac{150}{6}=x^2 \\\\\\ 25=x^2\implies \sqrt{25}=x\implies \boxed{5=x}[/tex]

3)

[tex]\bf \textit{volume of a square pyramid}\\\\ V=\cfrac{b^2h}{3}\quad \begin{cases} b=\textit{base's side}\\ h=height\\ -------\\ h=3\\ V=25 \end{cases}\implies 25=\cfrac{b^2\cdot 3}{3}\implies 25=b^2\cdot \cfrac{3}{3} \\\\\\ 25=b^2\cdot 1\implies 25=b^2\implies \sqrt{25}=b\implies \boxed{5=b}[/tex]

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