Frederick is working on a number puzzle and discovers that the product of the two base numbers is exactly twice as large as the sum of those same base numbers.
Help on this, please?
To solve this problem, we are going to use trial and error. If the 2 numbers are 3 and 4 then 3 and 4 is 12 and 3 + 4 = 7 which cannot be divided equally, so this is not the answer. 3 and 5 = 15 but this is not divisible by 2. 6 and 3 = 18 and 6 + 3 = 9 which is 1/2 of 18 therefore, one set is 6 and 3.
