The ages of five children are such that the second’s age is 3/4
the first’s. The third’s is 1/2
the first’s, the fourth’s is one less than the third’s, and the fifth’s is twice the fourth’s age
minus the second’s. If the sum of their ages is 33, how old is each child?

Respuesta :

Answer:

1st: 16

2nd: 12

3rd: 8

4th: 7

5th: -10

Step-by-step explanation:

1st age=x

2nd age=3/4x

3rd age=1/2x

4th age= 1/2x-1

5th age=2((1/2x-1)-(3/4x))

x+(3/4x)+(1/2x)+(1/2x-1)+2((1/2x-1)-(3/4x))=33

x=16