Answer:
yes, it is.
Step-by-step explanation:
An even function is that where for any x, f(-x)=-f(x).
So, suppose that f(x) and g(x) are even functions and define h(x)= f(x)+g(x). Then:
h(-x) = f(-x)+g(-x)
= -f(x)+(-g(x)) because f and g are even functions.
= -f(x)-g(x)
= -(f(x)+g(x))
= -h(x).
Then, h(x) is an even function.