Knowing that: (Equation to find the pH of a solution) [tex]pH = -log[H+][/tex] Solving: [tex]pH = -log[H+][/tex] [tex]5.2 = - log [H+][/tex] Knowing that the exponential is the opposite operation of the logarithm, then we have: [tex][H+] = 10^{-5.2}[/tex] [tex]\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark[/tex]
