Respuesta :

TheAmerican1970
 to separate Ag+ from Cu2+___________________________ 

treat the solution of Ag+ and Cu2+ with cold dilute HCl 

Ag2+ will get precipitated as AgCl (white colour precipitate) 
[Ksp of 1st group cation chlorides are low] 

filter the solution and remove the precipitate 

then pass H2S through the already acidified solution 

Cu2+ will get precipitated as CuS (Black color precipitate) 
[Ksp of 2nd group cation sulphides are low] 


to separate Cu2+ from Bi3+______________________________ 

add a few drops of dilute HCl into the solution of Cu2+ and Bi3+ 

BiCl3 is formed ( CuCl doesnt form because because Ksp value of BiCl3 is less than Ksp value of CuCl) 

then dilute the solution by adding water 

BiCl3 react with water and forms BiOCl and get precipitated (white color precipitate) 

filter the solution and remove the precipitate 

then pass H2S through the already acidified solution 


Cu2+ will get precipitated as CuS (Black color precipitate) 
[Ksp of 2nd group cation sulfides are low]

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