Lead ions can be removed from solution by precipitation with sulfate ions. Suppose a solution contains lead(II) nitrate.

1) List the compounds involved in the reaction.
Lead (II) nitrate
Potassium sulfate
Lead (II) sulfate
Potassium nitrate.
2) Write the formula of every compound.
Lead (II) nitrate: Pg(NO3)2
Potassium sulfate: K2SO4
Lead (II) sulfate: PbSO4
Potassium nitrate: KNO3
3) Write the chemical equation
.
[tex]Pb(NO_3)_2+K_2SO_4\rightarrow PbSO_4+KNO_3[/tex]List the elements (or polyatomic ions) in the reactants.
Pb: 1
NO3: 2
K: 2
SO4: 1
List the elements (or polyatomic ions) in the products.
Pb: 1
NO3: 1
K: 1
SO4: 1
Balance K.
[tex]Pb(NO_3)_2+K_2SO_4\rightarrow PbSO_4+2KNO_3[/tex]List the elements (or polyatomic ions) in the reactants.
Pb: 1
NO3: 2
K: 2
SO4: 1
List the elements (or polyatomic ions) in the products.
Pb: 1
NO3: 2
K: 2
SO4: 1
4) Balanced chemical equation.
[tex]Pb(NO_3)_{2(aq)}+K_2SO_{4(aq)}\rightarrow PbSO_{4(s)}+2KNO_{3(aq)}[/tex].