The function fx) = 110(1.004)* models the population of rabbits, inthousands, in a state x years after 1990. What is the approximatepopulation of the rabbits in 2012?A 115,000aora8. 120,000Input ->-1990C 310,085,000aayo338,550,000TE

The following function models the population of rabbits, in thousands, in a state x years after 1990.
[tex]f(x)=110\cdot(1.004)^x[/tex]What is the approximate population of rabbits in 2012?
Count the number of years after 1990 to 2012.
That's 22 years so we have x = 22
Let us substitute x = 22 into the above function
[tex]\begin{gathered} f(22)=110\cdot(1.004)^{22} \\ f(22)=110\cdot(1.091796) \\ f(22)=120.09756 \end{gathered}[/tex]That is approximately 120 thousands or 120,000