The one-to-one functions g and h are defined as follows.g(x) = 4x - 3h={(-6, 3), (-4, 7), (3, -8), (6, 4)Find the following

It is given that
[tex]g(x)=4x-3[/tex]Now to find the inverse of g
Let
[tex]\begin{gathered} y=4x-3 \\ 4x=y+3 \\ x=\frac{y+3}{4} \end{gathered}[/tex]So
[tex]g^{-1}(x)=\frac{x+3}{4}[/tex]Now we know that
[tex](g^{-1}.g)(x)=\text{ x}[/tex]So
[tex](g^{-1}.g)(2)=2[/tex]And since
[tex]h(-6)=3[/tex]So
[tex]h^{-1}(3)=-6[/tex]