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Triangle JKL is rotated 270° counterclockwise about the origin to form triangle J'K'L'. What is the y-coordinate of point J'? y 6 5 4 K 3 2. 1 -6 -5 -4 -3 -2 1 2 3 4 0 -1 6 Jo -2 3 4 -5 L -6 Type the answer in the box.

Respuesta :

Rotation of 270° ,counterclockwise

Find center point of triangle

JK = √ 9^2 +5^2

. = √ 106

JL = √9^2 + 3^2

. = √90

KL = 8

Then now find point J'

Distance from J to origin = JO = √4^2+2^2 =√20

Angle is arctan (2/4) = 26.56°

Then new coordinates J' are

Angle 270+26.56 = 296.56°

From origin trace a line perpendicular to JO

then

y = √20• Cos 26°

y = 4

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