Find the equation of the line that is parallel to Y = x -3 and contains the point (3,-2)

Given:
The equation of the line is
[tex]y=x-3[/tex]Required:
Find the equation of the line that is parallel to the given line and contains the point (3,-2).
Explanation:
The given equation of the line is
[tex]y=x-3[/tex]Compare the equation with the equation
[tex]y=mx+c[/tex]The slope of the line m = 1.
Since the slope of the parallel lines is equal.
The equation of the line that is parallel to the given line is:
[tex]y=x+b[/tex]This line contains the point (3,-2).
[tex]\begin{gathered} -2=3+b \\ b=-5 \end{gathered}[/tex]Thus the equation of the parallel line is:
[tex]y=x-5[/tex]Final Answer:
[tex][/tex]