Calculate the height of the upper triangle, using the Pythagoras theorem
[tex]\begin{gathered} 25^2=7^2+h^2 \\ h^2\text{ = }625\text{ - 49} \\ h^2\text{ = }576 \\ h\text{ = }\sqrt[]{576} \\ h\text{ = }24 \end{gathered}[/tex]The length of the vertical diagonal = 2 x 24
The length of the vertical diagonal = 48m
[tex]\begin{gathered} \text{Area = }\frac{48\times14}{2} \\ \text{Area = }48\times7 \\ \text{Area = 336 m}^2 \end{gathered}[/tex]