Solution:
Given
[tex]W=13.12+0.6215T-11.37V^{0.16}+0.3965TV^{0.16}[/tex]
Given that T= 7 and V=20.2
Substitute T=7 and V=20.2 into the W above
[tex]\begin{gathered} W=13.12+0.6215T-11.37V^{0.16}+0.3965TV^{0.16} \\ \\ W=13.12\text{ + 0.6215\lparen7\rparen-11.37\lparen20.2}^{0.16})+0.3965(7)(20.2^{0.16}) \end{gathered}[/tex][tex]\begin{gathered} W=13.12+4.3505-18.39148+4.48949 \\ W=3.56851 \\ \\ The\text{ answer is W=3.56851 degree celsius} \\ \end{gathered}[/tex]
