Consider the function y=(x−5)2+2.(a) Give the coordinates of the vertex of the graph of the function.(b) Graph the function on a window that includes the vertex.

Given
[tex]y=(x-5)^2+2[/tex]
Procedure
(a) The vertex of a parabola is the point where the parabola crosses its axis of symmetry.
The vertex is at (5, 2)
(b)