Respuesta :

Solution

For this case we have the following terminal point:

a) -7pi/6

The reference angle is pi/6

The quadrant is II

The terminal point is:

[tex](-\frac{\sqrt[]{3}}{2},\frac{1}{2})[/tex]

b) -41 pi/4

The reference angle is pi/4

The quadrant is IV

The terminal point is:

[tex](\frac{\sqrt[]{2}}{2},-\frac{\sqrt[]{2}}{2})[/tex]