would I use sin for this? you dont need to answer im just checking im using the right sine

Using tangent function:
[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{_{\text{ }}adjacent} \\ \tan (38)=\frac{h}{70} \\ h=70\cdot\tan (38) \\ h\approx54.69ft \end{gathered}[/tex]