Answer:
- See https://brainly.com/question/23882263 for A and B parts of the first question
d)
- [tex]HF = \sqrt{EH^2+EF^2} = \sqrt{2^2+3^2} = \sqrt{13}[/tex]
#2
- [tex]d = \sqrt{2^2+5^2} = \sqrt{4+25} = \sqrt{29}[/tex]
#3
Diagonals are perpendicular. Side length of the rhombus:
- [tex]a = \sqrt{(8/2)^2+(6/2)^2} = \sqrt{4^2+3^2} = \sqrt{25} = 5[/tex]
Perimeter:
