The density of an object is the ratio of its mass and volume
The question is incomplete, as the mass and the volume (or radius) of the balls are not given.
So, I will give a general explanation.
Tennis Ball
Assume the mass of the tennis ball is:
[tex]m = 56g[/tex]
And the radius is:
[tex]r = 3.3cm[/tex]
The volume of the ball would be:
[tex]V = \frac 43 \pi r^3[/tex]
So, we have:
[tex]V = \frac 43 \times \frac{22}{7} \times 3.3^3[/tex]
[tex]V = 150.59[/tex]
The density of the ball is:
[tex]D = \frac mV[/tex]
So, we have:
[tex]D = \frac {56}{150.59}[/tex]
[tex]D = 0.37gcm^{-3}[/tex]
From the calculations above, we can conclude that the tennis ball will float in water, because [tex]0.37gcm^{-3}[/tex] is less than the density of water, [tex]1gcm^{-3[/tex].
Golf Ball
Assume:
[tex]m = 47g[/tex]
[tex]r = 2.12cm[/tex]
The volume is:
[tex]V = \frac 43 \pi r^3[/tex]
So, we have:
[tex]V = \frac 43 \times \frac{22}{7} \times 2.12^3[/tex]
[tex]V = 39.93[/tex]
So, the density is:
[tex]D = \frac mV[/tex]
[tex]D = \frac{47}{39.93}[/tex]
[tex]D = 1.18gcm^{-3}[/tex]
From the calculations above, we can conclude that the tennis ball will sink in water, because [tex]1.18gcm^{-3}[/tex] is greater than the density of water, [tex]1gcm^{-3[/tex].
Read more about density at:
https://brainly.com/question/9196460