The density of an object is the ratio of its mass and volume
- The tennis ball would float in water, because it has a density of [tex]D = 0.37gcm^{-3}[/tex].
- The golf ball would sink because it has a density of [tex]D = 1.18gcm^{-3}[/tex]
The question is incomplete, as the mass and the volume (or radius) of the balls are not given.
So, I will give a general explanation.
Tennis Ball
Assume the mass of the tennis ball is:
[tex]m = 56g[/tex]
And the radius is:
[tex]r = 3.3cm[/tex]
The volume of the ball would be:
[tex]V = \frac 43 \pi r^3[/tex]
So, we have:
[tex]V = \frac 43 \times \frac{22}{7} \times 3.3^3[/tex]
[tex]V = 150.59[/tex]
The density of the ball is:
[tex]D = \frac mV[/tex]
So, we have:
[tex]D = \frac {56}{150.59}[/tex]
[tex]D = 0.37gcm^{-3}[/tex]
From the calculations above, we can conclude that the tennis ball will float in water, because [tex]0.37gcm^{-3}[/tex] is less than the density of water, [tex]1gcm^{-3[/tex].
Golf Ball
Assume:
[tex]m = 47g[/tex]
[tex]r = 2.12cm[/tex]
The volume is:
[tex]V = \frac 43 \pi r^3[/tex]
So, we have:
[tex]V = \frac 43 \times \frac{22}{7} \times 2.12^3[/tex]
[tex]V = 39.93[/tex]
So, the density is:
[tex]D = \frac mV[/tex]
[tex]D = \frac{47}{39.93}[/tex]
[tex]D = 1.18gcm^{-3}[/tex]
From the calculations above, we can conclude that the tennis ball will sink in water, because [tex]1.18gcm^{-3}[/tex] is greater than the density of water, [tex]1gcm^{-3[/tex].
Read more about density at:
https://brainly.com/question/9196460
