Calculate the density of each ball. Use the formula

D = m/V
where D is the density, m is the mass, and V is the volume. Record your calculations in Table A of your Student Guide.

Given that the density of water is 1.0 g/cm3, make a prediction about whether each ball will float in water. Record your prediction in Table A.

What is the density of the table tennis ball? Record your answer to the nearest hundredth.

g/cm3

What is the density of the golf ball? Record your answer to the nearest hundredth.

g/cm3

The tennis ball would float in water, because it has a density of [tex]D = 0.37gcm^{-3}[/tex].
The golf ball would sink because it has a density of [tex]D = 1.18gcm^{-3}[/tex]

The question is incomplete, as the mass and the volume (or radius) of the balls are not given.

So, I will give a general explanation.

Tennis Ball

Assume the mass of the tennis ball is:

[tex]m = 56g[/tex]

And the radius is:

[tex]r = 3.3cm[/tex]

The volume of the ball would be:

[tex]V = \frac 43 \pi r^3[/tex]

So, we have:

[tex]V = \frac 43 \times \frac{22}{7} \times 3.3^3[/tex]

[tex]V = 150.59[/tex]

The density of the ball is:

[tex]D = \frac mV[/tex]

So, we have:

[tex]D = \frac {56}{150.59}[/tex]

[tex]D = 0.37gcm^{-3}[/tex]

From the calculations above, we can conclude that the tennis ball will float in water, because [tex]0.37gcm^{-3}[/tex] is less than the density of water, [tex]1gcm^{-3[/tex].

Golf Ball

Assume:

[tex]m = 47g[/tex]

[tex]r = 2.12cm[/tex]

The volume is:

[tex]V = \frac 43 \pi r^3[/tex]

So, we have:

[tex]V = \frac 43 \times \frac{22}{7} \times 2.12^3[/tex]

[tex]V = 39.93[/tex]

So, the density is:

[tex]D = \frac mV[/tex]

[tex]D = \frac{47}{39.93}[/tex]

[tex]D = 1.18gcm^{-3}[/tex]

From the calculations above, we can conclude that the tennis ball will sink in water, because [tex]1.18gcm^{-3}[/tex] is greater than the density of water, [tex]1gcm^{-3[/tex].