asiadoll0717
asiadoll0717
03-09-2020
Mathematics
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Let x, y, z be numbers. (x2 yz4)3 =
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alloplgmax
alloplgmax
03-09-2020
I’m not sure I think it ended up being x2yz4
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(3 ^ - 2 * 2 ^ 3 * 5 ^ - 3)/(3 ^ 5 * 2 ^ - 6 * 5 ^ 4)
