Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction

Pb
(
NO
3
)
2
(
aq
)
+
2
NH
4
I
(
aq
)

PbI
2
(
s
)
+
2
NH
4
NO
3
(
aq
)

What volume of a
0.550
M NH4I solution is required to react with
751
mL of a
0.380
M Pb(NO3)2 solution?

volume:
mL

How many moles of PbI2 are formed from this reaction?