Given the time of flight for a projectile fired horizontally was o.66 seconds, and it landed 3:3 m from where it was launched, the projectile's muzzle velocity was: (A) 0.20 m/s, (B) 0.22 m/s, (C) 0.50 m/s, (D) 5.0 m/s, (E) none of the above.

Respuesta :

Answer:

Option (D)

Explanation:

In the projectile motion

Horizontal distance = horizontal velocity × time

3.3 = u × 0.66

u = 5 m/s

Muzzle velocity is 5 m/s