Respuesta :

[tex]\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] ~\dotfill\\\\ e^{\ln(5x)}\implies e^{\log_e(5x)}\implies 5x[/tex]

Answer:

C 5x

Step-by-step explanation:

e ^ ln (5x)

e^ and ln are inverses of each other

e^ ln cancels out

5x