fill in the missing numbers to complete the linear equation that gives the rule for this table. 8th grade

to find the slope of any straight line, we can simply use two points on that line
[tex]\bf \begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 3&-12\\ \underline{4}&\underline{-16}\\ 5&-20\\ \underline{6}&\underline{-24} &\\ \cline{1-2} \end{array}~\hspace{5em} (\stackrel{x_1}{4}~,~\stackrel{y_1}{-16})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-24}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-24-(-16)}{6-4}\implies \cfrac{-24+16}{6-4}[/tex]
[tex]\bf \cfrac{-8}{2}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-16)=-4(x-4) \\\\\\ y+16=-4x+16\implies y=-4x+0[/tex]