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A 4.700 L sample of gas is cooled from 71.0 °C to a temperature at which its volume is 3.300 L. What is this new temperature? Assume no change in pressure of the gas.

Respuesta :

initial condition : Vi = 4.700 L , Ti = 71.0ºC +273 => 344 K

final condition : Vf = 3.300 L , Tf = ?

Pressure is constant:

According to charle's law , volume is directly proportional to temperature at constant pressure !

Hence  Vi / Ti  = Vf / Tf

4.700 L / 344 K = 3.300 L / Tf

Tf =  3.300 L * 344 K / 4.700 L

Tf = 1135200 / 4.700

Tf = 241.53 K

Tf = 241.53 - 273

Tf = -31.47ºC